dua pegas identik (konstanta 100 n/m) dirangkai parallel . jika ujung diberi beban 1 kg (g =10 m/s) maka pertambahan panjangnya ?

ELASTISITAS
• energi

konstanta pegas rangkaian paralel
kₚ = n k
kₚ = 2 × (100 N/m)
kₚ = 200 N/m

berat beban
F = w = m g
F = (10 kg) (10 m/s²)
F = 100 N

Hk. Hooke
F = k ∆x
100 N = (200 N/m) ∆x
∆x = ½ m ✓