2log3=a dan 3log5=b nilai 5log120=

2log 3 = a, 3log 5 = b
5log 120
= log 120 / log 5
= log (8x3x5) / log 5
= (log 8 + log 3 + log 5) / log 5
= (log 2^3 + log 3 + log 5) / log 5
= (3. log 2 + log 3 + log 5) / log 5
(nanti bilangan pokok logariitma dengan 3 )
= (3. 3log 2 + 3log 3 + 3loog 5) / 3log 5
= (3/a + 1 + b) / b
= { (3 + a + ab) /a } / b
= (3 + a + ab) / ab



= (log

LogaRitMa

²log 3 = a
³log 5 = b

5'log 120
= ³log 120 / ³log 5
= ³log (2³ × 3 × 5) / ³log 5
= (3 . ³log 2 + ³log 3 + ³log 5) / ³log 5
= (3/a + 1 + b) / b
= (3 + a + ab) / ab ✔