Matematika

Pertanyaan

diketahui 2log3 = a dan 3 log 5 = b. nilai 6 log 120=

1 Jawaban

  • 6 log 120 = ³log120/³log6
    = ³log(2³ x 3 x 5)/³log(2x3)
    = (3 x ³log2 + ³log3 + ³log5)/(³log2 + ³log5)
    = (3/a + a/a + ab/a)/(1/a + b)
    = (3+a+ab)/a x a/(1+ab)
    = (a + ab + 3)/(1 + ab )

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