Matematika

Pertanyaan

diketahui sistem persamaan: x+y+2z=6; x-y+z=-4; 2x+y-2z=-4. nilai xyz

1 Jawaban

  • x+y+2z=6
    x-y+z=-4
    2x+y-2z=-4

    x+y+2z=6
    x-y+z=-4
    ________ -
    2y+1z =10.......(1)

    2x+y-2z=-4
    x-y+z=-4
    _________-
    1x-3z =0........(2)

    x+y+2z=6
    2x+y-2z=-4
    __________ -
    -1x+4z =10.......(3)


    1x-3z =0........(2)
    -1x+4z =10.......(3)
    ______________+
    1z = 10


    1x-3z =0........(2)
    x -3(10)=0
    x=30

    2y+1z =10.......(1)
    2y+10=10
    2y=0
    y=0

    xyz
    30.10.0
    0

    hasilnya 0

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