Materi Notasi Sigma Tunjukkan bahwa [tex] \displaystyle 8\sum_{k=4}^{15}k^2 - \sum_{k=1}^{12}(k+3)^2 = \sum_{k=1}^{12}(7k^2+42k+63)[/tex]
Matematika
ShanedizzySukardi
Pertanyaan
Materi Notasi Sigma
Tunjukkan bahwa
[tex] \displaystyle 8\sum_{k=4}^{15}k^2 - \sum_{k=1}^{12}(k+3)^2 = \sum_{k=1}^{12}(7k^2+42k+63)[/tex]
Tunjukkan bahwa
[tex] \displaystyle 8\sum_{k=4}^{15}k^2 - \sum_{k=1}^{12}(k+3)^2 = \sum_{k=1}^{12}(7k^2+42k+63)[/tex]
1 Jawaban
-
Pertanyaan Lainnya
