fungsi f(x)=px+q mempunyai f(-1)=2 dan f(1)=8 nilai f(4) adalah?

f(x)=px+q
f(-1)= -2p+q = 2
f(1) = p+q = 8 (kedua fungsi ini dikurangi supaya menghilangkan 'q')
-2p+q-p-q = 2-8
-3p = -6
p = 2

p+q = 8 => 2+q = 8 => q = 8-2 => q = 6

p = 2
q = 6

f(x) = 2x+6
f(4) = 2(4)+6
f(4) = 8+6 = 14

Semoga membantu yaa:)