persamaan kuadrat pakai rumus abc dari 2x kuadrat -4x-1=0

PK
• rumus abc

2x² - 4x - 1 = 0
a = 2, b = -4, c = -1

x₁₂ = (-b ± √(b² - 4 ac)) / 2a
x₁₂ = (-(4) ± √((-4)² - 4(2)(-1))) / (2 • 2)
x₁₂ = (4 ± √(16 + 8)) / 4
x₁₂ = (4 ± √24) / 4
x₁₂ = (4 ± 2√6) /4
x₁₂ = 4 ± ½√6

x₁ = 4 + ½√6
atau
x₂ = 4 - ½√6 ✓