Akar akar persamaan kuadrat 2xkuadrat-4x-3=0 adalah α dan β , maka nilai α/β + β/α adalah ?

2x^2 - 4x - 3 = 0
x = 2
y = -4
z = -3

a + b = - y/x
a + b = -(-4/2)
a + b = -(-2)
a + b = 2

ab = z/x
ab = -3/2

a/b + b/a
= a^2 / ab + b^2 / ab
= (a^2 + b^2)/ab
= [(a + b)^2 - 2ab]/ab

= [2^2 - 2(-3/2)]/(-3/2)
= [4 + 3]/(-3/2)
= 7/(-3/2)
= 7 × (-2/3)
= -14/3
= -4 2/3