assalamuallaikum.. tolong d bantu.. y..

jawab

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[tex] \frac{f(x+3)}{f(x-1)} \ = \frac{ 2^{x+3} }{ 2^{x-1} } \ = (2)^{x+3 -x+1} = 2^{4} = 16 [/tex]

f(x+3)/f(x-1) = 2^x+3/2^x+1= (2)^x+3-x+1= 2^4

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