f (x) = 1/2 x³ + 1 tentukan f pangkat min 1 (x) minta bantuan nya teman teman

f(x) = ½x³ + 1
y = ½x³ + 1
y - 1 = ½x³
2(y - 1) = x³
2y - 2 = x³
x³ = 2y - 2
x = ³√(2y - 2)
f-¹(x) = ³√(2x - 2)