sistem persamaan linear dua variabel[tex] \frac{x-1}{6} + y =6 x+ \frac{y-1}{4} =8[/tex]
Matematika
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Pertanyaan
sistem persamaan linear dua variabel[tex] \frac{x-1}{6} + y =6
x+ \frac{y-1}{4} =8[/tex]
x+ \frac{y-1}{4} =8[/tex]
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1. Jawaban Anonyme
jawab
(x-1)/6 + y = 6 } kali 6
x - 1 + 6y = 36
x + 6y = 37
x + (y -1)/4 =8 } kali 4
4x + y - 1= 32
4x + y = 33
x + 6y = 37 } kali 4
4x + y = 33
4x + 24 y = 148
4x + y = 33 | (--)
23 y = 115
y = 5
4x + y = 33
4x + 5 = 33
4x = 28
x = 7
(x,y)= (7,5)