Hitung integral (3x-3 + 2x^-2) dx dengan cara.

jawab

∫  (3x⁻³ + 2x⁻² ) dx

= 3/(-3+1) (x)⁻³⁺¹  + 2/(-2+1) (x)⁻²⁺¹ + c
= 3/-2 (x)⁻² + 2/(-1) (x)⁻¹ + c
=  - 3/2 x⁻² - 2 x⁻¹ +c
= - 3/(2x²) - 2/(x) + c