Tentukan nilai x yang memenuhi persamaan

LogAritMa

log (x - 3)^(x² - 6x + 14) = log (x² - 6x + 9)^(4x² - 4x + 1)
(x - 3)^(x² - 6x + 14) = (x - 3)^2(4x² - 4x + 1)
x² - 6x + 14 = 8x² - 8x + 2
7x² - 2x - 12 = 0
a = 7
b = -2
c = -12

Rumus ABC
x1.2 = (-b ± √(b² - 4ac))/2a
x1.2 = (2 ± √(4 + 84))/14
x1.2 = (2 ± 2√22)/14

Syarat numerus : > 0

NiLai x yg memenuhi :
x = (1 + √22)/7