Diketahui 6 gram urea (mr=60) dilarutkan dalam 250 gram air jika kb=0,52 dan kf=1,86 tentukan titik didih larutan dan titik beku larutan

wt = 6 gram
Mr = 60
wp = 250 gram
Kb = 0,52
Kf = 1,86
Tb = ....................?
Tf = .....................?

ΔTb = m.Kb
= wt/Mr x 1000/wp x Kb
= 6/60 x 1000/250 x 0,52
= 0,208°C

Tb = Tb° + ΔTb
= 100 + 0,208
= 100,208°C

ΔTf = m.Kf
= wt/Mr x 1000/wp x Kf
= 6/60 x 1000/250 x 1,86
= 0,744°C

Tf = Tf° - ΔTf
= 0 - 0,744
= -0,744°C