c. 12 gram kalium klorida dalam 200 ml larutan d. 400 mg calsium sulfat dalam 500 ml larutan
Kimia
Zidan1811
Pertanyaan
c. 12 gram kalium klorida dalam 200 ml larutan
d. 400 mg calsium sulfat dalam 500 ml larutan
d. 400 mg calsium sulfat dalam 500 ml larutan
1 Jawaban
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1. Jawaban AiniLavoisier
[c]
KCl
Mr = 75
ek = 1
wt = 12 gram
V = 200 mL
N = ........................?
BE = Mr/ek
= 75/1
= 75
N = wt/BE x 1000/V
= 12/75 x 1000/200
= 0,8 normal
[d]
CaSO₄
Mr = 136
ek = 1
wt = 400 mg = 0,4 gram
V = 500 mL
N = ........................?
BE = Mr/ek
= 136/1
= 136
N = wt/BE x 1000/V
= 0,4/136 x 1000/500
= 0,006 normal