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Pertanyaan

c. 12 gram kalium klorida dalam 200 ml larutan
d. 400 mg calsium sulfat dalam 500 ml larutan

1 Jawaban

  • [c]
    KCl
    Mr = 75
    ek = 1
    wt = 12 gram
    V = 200 mL
    N = ........................?

    BE = Mr/ek
    = 75/1
    = 75

    N = wt/BE x 1000/V
    = 12/75 x 1000/200
    = 0,8 normal

    [d]
    CaSO₄
    Mr = 136
    ek = 1
    wt = 400 mg = 0,4 gram
    V = 500 mL
    N = ........................?

    BE = Mr/ek
    = 136/1
    = 136

    N = wt/BE x 1000/V
    = 0,4/136 x 1000/500
    = 0,006 normal

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