Hitung normalitas berikut a. 4,5 gram alumunium klorida dalam 150 ml larutan b. 15 gram barium hidroksida dalan 1,15 L larutan

[a]
AlCl₃
Mr = 133,5
ek = 3
wt = 4,5 gram
V = 150 mL
N = ...................?

BE = Mr/ek
= 133,5/3
= 44,5

N = wt/BE x 1000/V
= 4,5/44,5 x 1000/150
= 0,1 x 6,67
= 0,667 normal

[b]
Ba(OH)₂
Mr = 171
ek = 2
wt = 15 gram
V = 1,15 L =1150 mL
N = ........................?

BE = Mr/ek
= 171/2
= 85,5

N = wt/BE x 1000/V
= 15/85,5 x 1000/1150
= 0,175 x 0,87
= 0,152 normal