tentukan gradiengaris melalui titik titik a. (2,4) dan (3,6) b. (-1,3) dan (4,-2) tolong yh thx

Bab Persamaan Garis
Matematika SMP Kelas VIII

a] gradien = m
m = (y2 - y1)/(x2 - x1)
m = (6 - 4)/(3 - 2)
m = 2

b] gradien = m
m = (y2 - y1)/(x2 - x1)
m = (-2 - 3) / (4 - (-1))
m = -5/5
m = -1

MATEMATIKA
Persamaan Garis Lurus

a) y2 - y1 / x2 - x1
= 6 - 4 / 3 - 2
= 2/1
= 2

b) y2 - y1 / x2 - x1
= -2 - 3 / 4 - (-1)
= - 5 / 5
= - 1