xlog (x + 6) + xlog (x-1) = 2 + xlog 2 adalah... a. (2,4) b. (2,3) c. (3,4) d. (3,5) e. (4,5)

jawab

ˣlog (x+6)  + ˣlog (x-1) = 2 + ˣlog 2
ˣlog (x+6)(x-1) = ˣlog x² + ˣlog 2
ˣlog (x²+5x -6) = ˣlog (x² )(2)
x²+ 5x - 6 = 2x²  , batas (x+6)(x-1) > 0, x² +2x > 0 , x > 0
-x²  +5x - 6 = 0
x² - 5x + 6 = 0
(x -3)(x  - 2) =0
x = 3  atau x = 2