Diketahui ABCD. EFGH panjang rusuk 12 lalu titik S ditengah BC jarak titik G ke AS (TLNG CARANYA YA)

Kubus
>> ABCD.EFGH

rusuk = 12 cm
AG = 12√3 cm
AS = √(AB² + BS²) = 6√5 cm
GS = AS = 6√5 cm

Perhatikan ∆ASG samakaki
Jarak S ke AG = garis tinggi ∆ASG dg alas AG = SP
SP = √(GS² - GP²)
SP = √(180 - (6√3)²)
SP = 6√2 cm

Jarak G ke AS = GQ

AG × SP = AS × GQ
12√3 × 6√2 = 6√5 × GQ
GQ = 12/5 √30 m

Jarak G ke AS = 12/5 √30 cm