penyelesaian dari sistem persamaan 4x-3y=-8 dan 5x + 2y=13 adalah (a-2,a+1)

4x - 3y = - 8 |×2
5x + 2y = 13 |×3

8x - 6y = - 16
15x + 6y = 39
---------------------( + )
23x = 23
x = 1

4x - 3y = - 8
4(1) - 3y = -8
- 3y = -8 - 4
- 3y = - 12
y = 4

( x , y ) = ( 1, 4 )
x = a - 2
1 = a - 2
a = 3
y = a + 1
4 = a + 1
a = 3
HP = a = 3