tiga bilangan berturut turut membentuk barisan aritmatika yaitu (p-1),(p+3),(3p-1). tentukan nilai p

Berdasarkan
[tex] b=U_2-U_1=U_3-U_2=...=U_n-U_{n-1}[/tex]
Diperoleh
[tex]b = U_2 - U_1 \\ b = (p+3)-(p-1) \\ b = p+3-p+1 \\ \therefore b =4...(1[/tex]
[tex] b=U_3-U_2 \\ b = (3p-1)-(p+3) \\ b = 3p-1-p-3 \\ \therefore b=2p-4 ...(2 [/tex]
Perhatikan bahwa pers. (1 dan pers.(2 sama.
[tex] 4=2p-4 \\ 4+4=2p \\ 8 = 2p \\ \therefore p = 4[/tex]
Jadi, [tex]p=4[/tex]